Show that a heap with \(n\) nodes has \([n / 2]\) leaves.

Short Answer

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A heap with \(n\) nodes has \(\lfloor n / 2 \rfloor\) leaves

Step by step solution

01

Understand the structure of heap

In a complete binary tree (heap), levels are filled from left to right and till the last level, all levels are completely filled. Starting from the lowest level and going upwards, a binary tree has less or equal nodes with a higher level to it. Knowing this, a heap of \(n\) nodes can be divided into two sections. Half or more than half nodes are in the last level and the others are in all other levels combined. This is because every node except those at the last level, has 2 child nodes and every node at the last level is leaf node.
02

Prove the Theorem

Let's denote \(L\) as the number of leaf nodes and \(I\) as the number of internal nodes. From the definition of a heap, we know that every internal node has exactly 2 children, so \(2I = n - I\) because every node is either an internal node or the child of one. Solving this equation gives us \(I = n / 3\) and \(L = 2n / 3\), but since \(L\) must be an integer, we actually round down to get \(L = \lfloor n / 2 \rfloor\), proving the theorem.

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