Given a list of \(n\) positive integers \((n \text { even }),\) divide the list into two sublists such that the difference between the sums of the integers in the two sublists is minimized. Is this problem an \(N P\) complete problem? Is this problem an \(N P\) -hard problem?

Short Answer

Expert verified
Yes, the described task complies with both the definition of NP-complete and NP-hard problems.

Step by step solution

01

Problem Definition

Given a list of \(n\) positive integers (where \(n\) is even), the task is to divide this list into two sublists such that the difference between the sum of integers in these sublists is minimized. This type of problem is known as a partition problem in the field of computer science and mathematics.
02

NP Problem Classification

A problem is considered NP (non-deterministic polynomial time) if its solution can be verified in polynomial time. Given a 'certificate' (proposed solution), we can easily verify if the partitions are valid and if the difference between their sums is minimized by simply calculating the sums and comparing.
03

NP-Completeness Assessment

A problem is NP-Complete if it is in NP and its solution can be obtained in polynomial time from a solution to any other problem in NP. The given problem is a variant of the partition problem, which is known to be NP-Complete. Therefore, this problem can also be solved in polynomial time given a solution to the partition problem. Hence, this problem is NP-Complete.
04

NP-Hardness Judgment

NP-Hard problems are at least as hard as the hardest problems in NP. Any NP problem can be reduced to any NP-Hard problem in polynomial time. Since this problem is NP-Complete, and any NP-Complete problem is by definition NP-Hard, we can conclude that this problem is also NP-Hard.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free