Consider a relation \(R(A, B, C, D, E)\) with the following dependencies: \\[ A B \rightarrow C, C D \rightarrow E, D E \rightarrow B \\] Is \(A B\) a candidate key of this relation? If not, is \(A B D ?\) Explain your answer.

Short Answer

Expert verified
'AB' is not a candidate key because it cannot identify every attribute in the relation. However, 'ABD' is a candidate key because it can uniquely identify every possible tuple in the relation.

Step by step solution

01

Test 'AB' as Candidate Key

First let's check whether 'AB' is a candidate key. Doing this involves determining the closure of AB, denoted as \(AB^+\). We start by adding the attributes that are part of the candidate key itself, so \(AB^+\) initially is AB. We then apply the functional dependencies. By applying the dependency \(AB \rightarrow C\), we get \(AB^+ = ABC\). There are no more dependencies that we can apply with the attributes in \(AB^+\), so we stop here.
02

Analyze Results

We look at the resulting \(AB^+\) and compare it to the original relation \(R(ABDE)\). Since AB does not uniquely identify D and E in every possible tuple of the relation, 'AB' is not a candidate key.
03

Test 'ABD' as Candidate Key

Now let's test whether 'ABD' is a candidate key. Using the same process, we start with \(ABD^+\ = ABD\). Applying the functional dependencies, the dependency \(CD \rightarrow E\) can be added because we now have \(D\) in \(ABD^+\). So, \(ABD^+ = ABDE\). We also apply the dependency \(AB \rightarrow C\), which doesn't add a new attribute as \(C\) is already in \(ABD^+\). No other dependencies can be added.
04

Analyze Results

We again compare the resulting \(ABD^+\) to the original relation \(R(ABCDE)\). This time, \(ABD^+\) contains all the attributes of \(R\), so 'ABD' can uniquely identify every possible tuple of the relation and therefore, 'ABD' is a candidate key.

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