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Chapter 15: Problem 6

How many different join orders are there for a query that joins 10 relations?

Short Answer

Expert verified
There are 3,628,800 different join orders for a query that joins 10 relations.

Step by step solution

01

Understanding permutations

A permutation is the arrangement of all the members of a set into some sequence or order. In this case the 10 relations can be arranged in different sequences or orders.
02

Calculate the number of permutations

In the general case, if there are \(n\) distinct objects, and we want to arrange all of them, the number of different arrangements is given by \(n!\), the factorial of \(n\). The factorial of a non-negative integer \(n\) is the product of all positive integers less than or equal to \(n\).
03

Apply the calculation to the problem

Here we have 10 different relations, so we need to calculate 10!. The factorial of 10, denoted by 10!, is equal to 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1.
04

Calculate the factorial

Multiplying all these numbers together, we get \(10! = 3,628,800\).

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