Chapter 9: Q19P (page 390)

Question: Let $E_{REX \hat{I}}$

Short Answer

Expert verified

We know that $PSPACE \emptyset EXSPACE$ i.e., the problem of any EXSPACE-complete cannot be in PSPACE.

Step by step solution

Using Regular expression with exponentiation

Consider the statement $E_{REX \hat{I}} = {< R >$ R is regular expression with exponentiation and

$L (R) = \emptyset$ }

From the above statement it can be understood that R is a regular expression and the language, which contains this regular expression consists NULL values.

Applying the concept of intractability

$E_{REX \hat{I}}$ is said to be intractable because it can be demonstrated in such a manner that is complete for the class EXSPACE.

From the above statements we can conclude that “any EXSPACE-complete problem cannot be in PSPACE and it is much less in P”.

Because PSPACE will be same as EXSPACE which is contradicting the corollary discussed above.

Hence, it can be said that $E_{REX \hat{I}} \in P$

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Question: Let $E_{REX \hat{I}}$

Short Answer

Step by step solution

Using Regular expression with exponentiation

Applying the concept of intractability

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Question: LetEREXI^

Short Answer

Step by step solution

Using Regular expression with exponentiation

Applying the concept of intractability

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Computer Science Textbooks

Computer Network

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Study anywhere. Anytime. Across all devices.

Question: Let $E_{REX \hat{I}}$