LetMULT={a#b#c|a,b,care binary natural numbers and a×b=c}. Showthat MULTL.

Short Answer

Expert verified

By clearing the that runs into the log space and proves MULT. So, the condition as MULTL.

Step by step solution

01

To Class the logarithmic space on the deterministic

The class L: L is the class of languages that are decidable in the logarithmic space on the deterministic truing machine. It shows L = SPACE (log n).

02

To Prove the condition MULT∈L

Let M be the DTM that decides the MULT in logarithmic space. decides,

The construction of M is,

M="Oninputa#b#c:

1. Reject if any of the three strings aren't a binary number as stated above.

2. Set up a binary counter named i those points to the letter O.

3. Set the maximummax(0,i+1-lengthof1)for a binary counter j.

4. Set a binary counter from k to i - j to start.

5. Now add xx+a[j]*b[k]to the binary counter.

6. Repeat steps 3–5 minutes (i,n-1)times.

7. Calculate x=floorx2by repeating steps 2n -1 times.

Thus, by clearing the that runs into the log space and decides MULT.

So, it proves the condition as MULTL.

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