What is the output of the following (when embedded in a complete program \() ?\) int count \(=3\); while (count- - > 0) cout \(<<\) count \(<<\) " ";

Short Answer

Expert verified
Answer: The output is "3 2 1 ".

Step by step solution

01

Initialize the variable

Initialize the variable 'count' with the value 3.
02

Analyze the while loop condition

The while loop condition is (count-- > 0). The loop will continue running as long as the condition is true, meaning the 'count' value is greater than 0. The '--' is a post-decrement operator, which means the value of 'count' is decremented after it is compared with 0.
03

Analyze the loop body and output

Inside the while loop, we have a single statement: cout << count << " "; This statement will print the value of 'count' followed by a space.
04

Execute the loop and track the output

1. In the first iteration, 'count' has a value of 3. The loop condition checks if 3 > 0, which is true. Then the post-decrement operator decrements 'count' to 2. The output is "3 ". 2. In the second iteration, 'count' has a value of 2. The loop condition checks if 2 > 0, which is true. Then the post-decrement operator decrements 'count' to 1. The output is "3 2 ". 3. In the third iteration, 'count' has a value of 1. The loop condition checks if 1 > 0, which is true. Then the post-decrement operator decrements 'count' to 0. The output is "3 2 1 ". 4. In the fourth iteration, 'count' has a value of 0. The loop condition checks if 0 > 0, which is false. The loop stops executing.
05

Final output

The output of the given code snippet when embedded in a complete program is "3 2 1 ".

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