What is the output of the following (when embedded in a complete program \() ?\) int count \(=3\); while (- -count > 0) cout < < count < < " " ;

Short Answer

Expert verified
Answer: The output of the code is "2 1 ".

Step by step solution

01

Initialize the variable

Start by initializing the variable 'count' with the value 3.
02

Check the loop condition

The loop has the condition `--count > 0`. In the first iteration, `--count` means 'decrement count by 1 and then check its value.' So, count becomes 2 and the condition becomes `2 > 0` which is true. Therefore, the loop will continue with its first iteration.
03

Output the value of 'count'

In the first iteration, the value of 'count' is 2 after the decrement operation. The loop body will output the value of the count followed by a space. So, the output will be "2 ".
04

Check the loop condition again

As the loop continues, the loop condition `--count > 0` is checked again. This time, the value of 'count' is 1 after decrementing. The condition becomes `1 > 0` which is true. Therefore, the loop will proceed to its second iteration.
05

Output the value of 'count' again

In this second iteration, the value of 'count' is 1 after the decrement operation. The loop body will output the value of the count followed by a space. So, the output will now be "2 1 ".
06

Check the loop condition for the third time

The loop continues and the loop condition `--count > 0` is checked for the third time. This time, the value of 'count' is 0 after decrementing. The condition becomes `0 > 0` which is false. Therefore, the loop will exit.
07

Final output

Since the loop has exited, there will be no more changes to the output. The final output of the code is "2 1 ".

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