What is the output of the following (when embedded in a complete program \() ?\) for \((\text { int count }=1 ; \text { count }<5 ; \text { count }++)\) cout \(<<(2 * \text { count })<<\) " ";

Short Answer

Expert verified
Answer: The output of the program is "2 4 6 8".

Step by step solution

01

Identify the structure of the for loop

The for loop in C++ is written as: for (initialization; condition; increment/decrement) { // code to be executed } In this exercise, the for loop is: for (int count = 1; count < 5; count++) { // code to be executed } The loop initializes the variable count with the integer value 1. In each iteration, the loop checks if the condition "count < 5" is true. If so, it runs the code within the loop. After the code execution, the "count" variable increments by 1 (++ operator). It will continue executing the loop until the condition is false.
02

Analyze the code within the loop

In the given code, the loop contains the following output command: cout << (2 * count) << " "; It multiplies the loop counter "count" with 2 and displays the result followed by a space. This process repeats in each iteration of the loop.
03

Calculate and list the outputs for each iteration

We'll now find the output for each iteration: 1. When count = 1: 2 * 1 = 2 2. When count = 2: 2 * 2 = 4 3. When count = 3: 2 * 3 = 6 4. When count = 4: 2 * 4 = 8
04

Combine the outputs

The final output is a sequence of numbers obtained from the loop, separated by spaces: 2 4 6 8

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