Chapter 4: Problem 12

Write a function definition for a function called even that takes one argument of type \(i n t\) and returns a bool value. The function returns true if its one argument is an even number; otherwise, it returns false.

Short Answer

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Question: Write a function called "even" that takes an integer as an argument and returns a boolean value. The function should return true if the integer is even and false otherwise.

Step by step solution

Write the function signature

To begin, write the function signature which includes the function's name `even`, the input argument `int` for the integer, and `bool` as the return type for the function. ```cpp bool even(int num); ```

Implement the function body

Inside the function, use an if statement to check if the integer `num` is even. If it is (i.e., `num % 2 == 0`), return `true`. Otherwise, return `false`. Here's the complete function implementation: ```cpp bool even(int num) { if (num % 2 == 0) { return true; } else { return false; } } ```

Alternate Implementations

As an alternative, you can also use a ternary operator instead of the if-else statement to make the function shorter and more concise: ```cpp bool even(int num) { return (num % 2 == 0) ? true : false; } ``` Or even more simply, just return the result of the expression since it is a boolean value: ```cpp bool even(int num) { return num % 2 == 0; } ``` With these implementations, the `even` function checks if the input integer is even and returns the corresponding boolean value.

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Write a function definition for a function called even that takes one argument of type \(i n t\) and returns a bool value. The function returns true if its one argument is an even number; otherwise, it returns false.

Short Answer

Step by step solution

Write the function signature

Implement the function body

Alternate Implementations

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