What output will be produced when the following line is executed (assuming the line is embedded in a complete and correct program with the proper include directives)? cout << "*" << setw(3) << 12345 << "*" << endl;

Short Answer

Expert verified
Answer: The output is *12345*

Step by step solution

01

Understand the given code

The given code is a single line that uses "cout" to print a sequence of characters followed by an integer and an asterisk. The "setw()" function is used to specify the width of the integer output. We need to determine the output that results from executing this line.
02

Explain the setw() function

The "setw()" function is a part of the library and stands for "set width." It is used to set the field width of the output to the specified value. In this example, the value is set to 3. This affects the output of the next item, which is the integer value 12345.
03

Determine the effect of setw(3) on the integer 12345

Since the width is set to 3, the integer 12345 will be truncated to fit within the field width. However, the integer 12345 is longer than the specified width of 3; thus, the "setw()" function will not truncate or change the integer in this case, and the entire integer will be printed.
04

Combine the output parts

Now that we know how each part of the code affects the output, we can combine the parts using the sequence they are printed in the code: 1. An asterisk (*) is printed. 2. The integer 12345 is printed, without any effect due to "setw(3)" since 12345 is longer than the specified width. 3. Another asterisk (*) is printed. 4. a new line is inserted using "endl." Putting these parts together, we can determine the final output.
05

Final Output

The output produced by this line of code is as follows: *12345*

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