What is the output produced by the following code? int my_array[4][4], index1, index2; for (index1 = 0; index1 < 4; index1++) for (index2 = 0; index2 < 4; index2++) my_array[index1][index2] = index2; for (index1 = 0; index1 < 4; index1++) { for (index2 = 0; index2 < 4; index2++) cout << my_array[index1][index2] << " "; cout << endl; }

First, we need to initialize the 2D integer array my_array[4][4] and declare the integer variables index1 and index2. This 2D array will temporarily store integer values.

We use nested for loops to iterate through all the elements in the 2D array (my_array). For each element, we assign the value of index2. Thus, the value in the matrix will be equal to the column index.

We use another set of nested for loops to iterate through all the elements in the 2D array (my_array). Inside the inner loop, we print the current element followed by a space. Outside the inner loop, but still inside the outer loop, we print an endline character to move to the next row. Based on these steps, we can now walk through the code to find the output: On the first iteration of both filling loops: index1 = 0, index2 = 0, my_array[0][0] = index2 = 0; On the first iteration of the inner loop and the second iteration of the outer loop: index1 = 0, index2 = 1, my_array[0][1] = index2 = 1; On the first iteration of the inner loop and the third iteration of the outer loop: index1 = 0, index2 = 2, my_array[0][2] = index2 = 2; On the first iteration of the inner loop and the fourth iteration of the outer loop: index1 = 0, index2 = 3, my_array[0][3] = index2 = 3; This first row of the matrix contains values [0, 1, 2, 3] This process is performed for all rows (0-3), so the output will be a matrix where each row has values [0, 1, 2, 3]. Therefore, the output produced by the code will be: 0 1 2 3 0 1 2 3 0 1 2 3 0 1 2 3