Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 8: Problem 5

What is the maximum length of a string that can be placed in the string variable declared by the following declaration? Explain. char s [6];

Short Answer

Expert verified
Answer: The maximum length of a string that can be placed in a string variable declared with the size of 6 is 5 characters. This is because the null character `\0`, which marks the end of the string, occupies one character space in the array.

Step by step solution

01

Understand the string variable declaration

The given declaration `char s[6]` is a character array that can store up to 6 characters. It is important to note that this array also includes the null character `\0` that is necessary to mark the end of the string.
02

Calculate the maximum string length

Since the null character `\0` occupies one character space in the array, the maximum number of characters that can be stored as a part of the string is one less than the total size of the array. In this case, the array has a size of 6; hence, the maximum string length would be 5 characters.
03

Explain the reasoning

The null character `\0` is crucial in strings as it indicates the end of a string. It is automatically added to every string, so when calculating the maximum length of a string that can be stored in the character array, the null character should always be taken into account. As a result, in the given array with size 6, the maximum length of the string that can be stored is 5 characters plus the null character at the end, occupying all six character spaces.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What (if anything) is wrong with the following code? char string_var[] = "Hello"; strcat(string_var, " and Good-bye."); cout \(<<\) string_var Assume that the code is embedded in a complete program, and that an include directive for \(\) is in the program file.

Which of the following declarations are equivalent? char string_var[10] = "Hello"; char string_var[10] \(=\left\\{^{\prime} \mathrm{H}^{\prime},^{\prime} \mathrm{e}^{\prime},^{\prime} \mathrm{L}^{\prime},^{\prime} \mathrm{l}^{\prime}, \text { ' o' },^{\prime} \backslash \theta^{\prime}\right\\} ;\) char string_var[10] \(=\left\\{^{\prime} \mathrm{H}^{\prime},^{\prime} \mathrm{e}^{\prime},^{\prime} \mathrm{l}^{\prime},^{\prime} \mathrm{l}^{\prime}, \text { 'o' }\right\\} ;\) char string_var[6] = "Hello"; char string_var[] = "Hello";

Consider the following code (and assume it is embedded in a complete and correct program and then run): char my_string[80]; cout << "Enter a line of input:\n"; cin.getline(my_string, 6); cout << my_string << "

Suppose the function strlen (which returns the length of its string argument \()\) was not already defined for you. Give a function definition for strlen. Note that strlen has only one argument, which is a C string. Do not add additional arguments; they are not needed.

How many characters are in each of the following character and string constants? a. '/n' b. 'n' c. "Mary" d. "M" e. "Maryln"
See all solutions

Recommended explanations on Computer Science Textbooks

Algorithms in Computer Science

Read Explanation

Functional Programming

Read Explanation

Computer Network

Read Explanation

Theory of Computation

Read Explanation

Data Structures

Read Explanation

Data Representation in Computer Science

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free