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Chapter 7: Problem 9

Declare a structure named Tempscale, with the following members fahrenheit: a double centigrade: a double Next, declare a structure named Reading, with the following members: windSpeed: an Int humfdity: a double temperature: a Tempscale structure variable Next, define a Reading structure variable named today. Now write statements that will store the following data in the Reading variable. Wind speed: \(37 \mathrm{mph}\) Humidity: 3296 Fahrenheit temperature: 32 degrees Centigrade temperature: 0 degrees

Short Answer

Expert verified
Answer: The Tempscale structure has two members: 'fahrenheit' and 'centigrade', both of type double.

Step by step solution

01

1. Declare Tempscale structure

Start by declaring the Tempscale structure with two members: fahrenheit and centigrade, both of type double. ```cpp struct Tempscale { double fahrenheit; double centigrade; }; ```
02

2. Declare Reading structure

Declare the Reading structure, which includes: windSpeed as an int, humidity as a double, and temperature as a Tempscale structure. ```cpp struct Reading { int windSpeed; double humidity; Tempscale temperature; }; ```
03

3. Create a Reading variable

Define a Reading structure variable named "today". ```cpp Reading today; ```
04

4. Store the given data in the Reading variable

Write statements that will store the data (wind speed, humidity, and temperature in both Fahrenheit and Centigrade) in the Reading variable "today". ```cpp today.windSpeed = 37; today.humidity = 32.96; today.temperature.fahrenheit = 32; today.temperature.centigrade = 0; ```

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