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Chapter 8: Problem 23

Look at the following array definition. int numbers \([5]=11,2,31\) A) What value is stored in numbers [2]\(?\) B) What value is stored in numbers [4]\(?\)

Short Answer

Expert verified
Answer: The value stored in numbers[2] is 31, and the value stored in numbers[4] is 0.

Step by step solution

01

Find the values at the indices

We are given the array definition `int numbers[5] = {11, 2, 31}`, and we want to find out the values at indices 2 and 4.
02

Value at index 2

In order to find the value at index 2, we need to look at the third value of the array. In this case, the value is 31. So, numbers[2] = 31.
03

Value at index 4

The given array has only three elements assigned, so the last two elements will have the default value for int data type in C++. The default value for int data type is 0 (zero). Therefore, numbers[4] = 0. So, the answers to the questions are: A) The value stored in numbers[2] is 31. B) The value stored in numbers[4] is 0.

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Most popular questions from this chapter

To allow an array of structures or an array of objects to be initialized, the struct or class declaration should include a(n) ________.

To pass an array to a function, pass the _______ of the array.

The ________ indicates the number of elements, or values, an array can hold.

Given the following array definition: \\[\text { Int values }[5]=(4,7,6,8,2)\\] What does the following statement display? $$\begin{array}{l} \text { cout }\langle\langle\text { values }[4] \ll x \quad \text { " }\langle\langle\quad \text { (values }[2]+\text { values }[3]) \\ \quad\langle\langle\quad \text { " } \quad \text { " } \quad\langle\langle\text { ++values }[1] \quad\langle\langle\text { end } 1 \end{array}$$

\(\mathrm{C}++\) has no array _________ checking, which means you can inadvertently store data past the end of an array.
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