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Chapter 1: Problem 32

The variable a starts with the value 1. The variable b starts with the value 10. The variable c starts with the value 100. The variable x starts with the value 0. Store the value of c times 3 in x. Add the value of b times 6 to the value already in x. Add the value of a times 5 to the value already in x. Display the value in x on the screen.

Short Answer

Expert verified
Answer: The final value of x is 335.

Step by step solution

01

Initialize the variables

First, assign the respective values to each variable: a = 1 b = 10 c = 100 x = 0
02

Multiply c by 3 and store in x

Next, multiply the value of c by 3 and assign the result to x: x = c * 3
03

Add b times 6 to the value of x

Now, multiply the value of b by 6, and add the result to the current value of x: x = x + (b * 6)
04

Add a times 5 to the value of x

Similarly, multiply the value of a by 5, and add the result to the current value of x x = x + (a * 5)
05

Display the value of x

Finally, display the value of x on the screen by using the print function: print(x)

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