Each of the following member functions for performing an operation on a linked list of type NumberList has at least one error. Explain what is wrong and how to fix it. A) NumberList: :printList ( ) while (head) cout \(<<\) head- \(>\) value head \(=\) head- \(>\) next B) NumberList: :printList ( ) ListNode \(\star \mathrm{p}=\) head; while \((\mathrm{p}->\text { next })\) cout \(<\) value \(p=p->n e x t\) C) NumberList: :printList ( ) Listrode \(* p=\) head while \((p)\) cout \(<\) value \(p++;\) D) NumberList: : NumberList ( ) ListNode \(*\) nodePtr, *nextNode; nodePtr = head; while (nodePtr != NULL) nextNode \(=\) nodePtr-next nodePtr- \(>\) next \(=\) NULL \(;\) nodePtr \(=\) nextNode;

Short Answer

Expert verified
A) NumberList::printList(): ``` NumberList::printList() while (head) cout << head->value head = head->next ``` B) NumberList::printList(): ``` NumberList::printList() ListNode *p = head; while (p->next) cout << p->value p = p->next ``` C) NumberList::printList(): ``` NumberList::printList() Listrode *p = head; while (p) cout << p->value p++; ``` D) NumberList::NumberList(): ``` NumberList::NumberList() ListNode *nodePtr, *nextNode; nodePtr = head; while (nodePtr != NULL) nextNode = nodePtr->next; nodePtr->next = NULL; nodePtr = nextNode; ``` #Answer# A) Here are the errors in the first version of NumberList::printList(): 1. The member function is missing return type "void". 2. The syntax for the while-loop is incorrect, as it doesn't have a starting "{" and a closing "}". 3. The code directly modifies the "head" pointer, which is not recommended. Corrected NumberList::printList() (Version A): ``` void NumberList::printList() { ListNode *current = head; while (current) { cout << current->value << " "; current = current->next; } cout << endl; } ``` B) Errors in the second version of NumberList::printList(): 1. The member function is missing return type "void". 2. The syntax for the while-loop is incorrect, as it doesn't have a starting "{" and a closing "}". 3. The last element won't be printed since it's checking for "p->next" in the while-loop condition. Corrected NumberList::printList() (Version B): ``` void NumberList::printList() { ListNode *p = head; while (p) { cout << p->value << " "; p = p->next; } cout << endl; } ``` C) Errors in the third version of NumberList::printList(): 1. The member function is missing return type "void". 2. The syntax for the while-loop is incorrect, as it doesn't have a starting "{" and a closing "}". 3. The pointer type is written incorrectly as "Listrode" instead of "ListNode". 4. It's using "p++" instead of "p = p->next" to move to the next node, which is incorrect. Corrected NumberList::printList() (Version C): ``` void NumberList::printList() { ListNode *p = head; while (p) { cout << p->value << " "; p = p->next; } cout << endl; } ``` D) Errors in the NumberList::NumberList() constructor: 1. The constructor is not initializing the head pointer to NULL; thus, it's not an empty list. 2. The syntax for the while-loop is incorrect, as it doesn't have a starting "{" and a closing "}". 3. It's trying to delete the nodes of a list, but the logic is incorrect and will lead to memory issues, as it's setting "next" to NULL before moving to the next element and there's no deallocation. Corrected NumberList::NumberList(): ``` NumberList::NumberList() { head = NULL; } ```

Step by step solution

01

A) Analyzing NumberList::printList() (version A)

Here's the provided code for this member function: ``` NumberList::printList() while (head) cout << head->value head = head->next ``` There are several issues with this code: 1. The member function is missing return type "void". 2. The syntax for the while-loop is incorrect, as it doesn't have a starting "{" and a closing "}". 3. The code directly modifies the "head" pointer, which is not recommended. Here is the corrected version:
02

A) Corrected NumberList::printList() (version A)

``` void NumberList::printList() { ListNode *current = head; while (current) { cout << current->value << " "; current = current->next; } cout << endl; } ```
03

B) Analyzing NumberList::printList() (version B)

Here's the provided code for this member function: ``` NumberList::printList() ListNode *p = head; while (p->next) cout << p->value p = p->next ``` There are a few issues in this code: 1. The member function is missing return type "void". 2. The syntax for the while-loop is incorrect, as it doesn't have a starting "{" and a closing "}". 3. The last element won't be printed since it's checking for "p->next" in the while-loop condition. Here is the corrected version:
04

B) Corrected NumberList::printList() (version B)

``` void NumberList::printList() { ListNode *p = head; while (p) { cout << p->value << " "; p = p->next; } cout << endl; } ```
05

C) Analyzing NumberList::printList() (version C)

Here's the provided code for this member function: ``` NumberList::printList() Listrode *p = head; while (p) cout << p->value p++; ``` There are a couple of issues in this code: 1. The member function is missing return type "void". 2. The syntax for the while-loop is incorrect, as it doesn't have a starting "{" and a closing "}". 3. The pointer type is written incorrectly as "Listrode" instead of "ListNode". 4. It's using "p++" instead of "p = p->next" to move to the next node, which is incorrect. Here is the corrected version:
06

C) Corrected NumberList::printList() (version C)

``` void NumberList::printList() { ListNode *p = head; while (p) { cout << p->value << " "; p = p->next; } cout << endl; } ```
07

D) Analyzing NumberList::NumberList()

Here's the provided code for this member function: ``` NumberList::NumberList() ListNode *nodePtr, *nextNode; nodePtr = head; while (nodePtr != NULL) nextNode = nodePtr->next; nodePtr->next = NULL; nodePtr = nextNode; ``` There are a few issues in this code: 1. The constructor is not initializing the head pointer to NULL; thus, it's not an empty list. 2. The syntax for the while-loop is incorrect, as it doesn't have a starting "{" and a closing "}". 3. It's trying to delete the nodes of a list, but the logic is incorrect and will lead to memory issues, as it's setting "next" to NULL before moving to the next element and there's no deallocation. Here is the corrected version:
08

D) Corrected NumberList::NumberList()

``` NumberList::NumberList() { head = NULL; } ```

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