To indicate that a linked list is empty, you should set the pointer to its head to the value __________.

Short Answer

Expert verified
Answer: To indicate that a linked list is empty, you should set the pointer to its head to the value 'null'.

Step by step solution

01

Understanding Linked Lists

A linked list is a linear data structure made of nodes that store data and hold a reference (a pointer) to the next node in the sequence. The first node in the sequence is called the head. When a linked list is empty, it means there are no nodes in the list.
02

Indicating an Empty Linked List

To indicate that a linked list is empty, you should set the pointer to its head to a specific value. This value should represent that there is no valid node in the list.
03

Assigning a Null Value to the Head Pointer

In most programming languages, we can use a special value called 'null' to indicate "no reference" or "no value." By setting the head pointer of the linked list to 'null', we can indicate that there are no nodes in the list and the linked list is empty. So, to indicate that a linked list is empty, you should set the pointer to its head to the value 'null'.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Each of the following member functions for performing an operation on a linked list of type NumberList has at least one error. Explain what is wrong and how to fix it. A) NumberList: :printList ( ) while (head) cout \(<<\) head- \(>\) value head \(=\) head- \(>\) next B) NumberList: :printList ( ) ListNode \(\star \mathrm{p}=\) head; while \((\mathrm{p}->\text { next })\) cout \(<\) value \(p=p->n e x t\) C) NumberList: :printList ( ) Listrode \(* p=\) head while \((p)\) cout \(<\) value \(p++;\) D) NumberList: : NumberList ( ) ListNode \(*\) nodePtr, *nextNode; nodePtr = head; while (nodePtr != NULL) nextNode \(=\) nodePtr-next nodePtr- \(>\) next \(=\) NULL \(;\) nodePtr \(=\) nextNode;

Write a function double lastValue(ListNode *ptr) that returns the value stored in the last node of a nonempty list passed to it as parameter. The function should print an error message and terminate the program if the list passed to it is empty.

You are the leader of a programming team. You want the programmers on your team to attend a two-day workshop on linked lists, stacks and queues. One of the managers points out that the STL already supplies each one of those data structures, making it unnecessary for your programmers to write their own. Write the manager a short memo that justifies the need for the workshop.

The __________ points to the first node in a linked list.

Write a function void printSecond(ListNode *ptr) that prints the value stored in the second node of a list passed to it as parameter. The function should print an error message and terminate the program if the list passed to it has less than two nodes.

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free