Write a C++ statement that prints the message "The number is not valid." if the variable hours is outside the range 0 through 80.

Short Answer

Expert verified
Question: Write a C++ statement that checks if the variable "hours" is within the range 0 through 80, and if it's not, prints a message "The number is not valid." Answer: ```cpp if ( hours < 0 || hours > 80) { std::cout << "The number is not valid." << std::endl; } ```

Step by step solution

01

Initialize variable "hours" with some value

First, you need to declare and initialize an integer variable "hours" to some value, which will be later checked if it is within the valid range. Here is an example of how you can do it: ```cpp int hours = 50; // This value can be any number that represents the number of hours. ```
02

Use if statement and comparison operators to check the range

Next, you need to implement an if statement to check if the "hours" variable is outside the range 0 through 80. To do that, you can use comparison operators such as "greater than" (>) or "less than" (<) and logical operator "OR" (||). Here's how you can check if "hours" is outside the valid range: ```cpp if ( hours < 0 || hours > 80) { ```
03

Print the message if "hours" is outside the valid range

Since the conditions in Step 2 check if "hours" is outside the valid range, you can now print a message "The number is not valid." within this if statement: ```cpp std::cout << "The number is not valid." << std::endl; ``` To complete the if statement, you must close the braces: ```cpp } ```
04

Final code

Combining all the steps, the final C++ code should look like this: ```cpp #include int main() { int hours = 50; // This value can be any number that represents the number of hours. // Check if hours is outside the range 0 through 80 if ( hours < 0 || hours > 80) { std::cout << "The number is not valid." << std::endl; } return 0; } ```

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