The __________ statement causes a loop to terminate immediately.

Short Answer

Expert verified
Answer: The "break" statement is used to terminate a loop immediately.

Step by step solution

01

Identify common loop control statements

In most programming languages, the common loop control statements are "break" and "continue". The "break" statement is used to terminate the loop immediately. The "continue" statement is used to skip the current iteration and continue with the next one, without terminating the loop.
02

Choose the correct statement

Since the exercise asks for the statement that causes a loop to terminate immediately, the correct answer is the "break" statement.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

include \(<\) iostream \(>\) using namespace std; int main() \\{ int choice, num1, num2; do \\{ cout \(<<\) "Enter a numbe… # A) / / This program displays the sum of two numbers. # include \(<\) iostream \(>\) using namespace std; int main() \\{ int choice, num1, num2; do \\{ cout \(<<\) "Enter a number: "; \\[ \operatorname{cin} \quad>>\text { num1 } \\] cout \(<<\) "Enter another number: " \\[ \operatorname{cin} \quad>>\text { num2 } \\] cout \(<<\) "Their sum is " \(<<(\text { num1 }+\text { num2 ) }<<\) endl; cout \(<<\) "Do you want to do this again? \\[ \begin{array}{l} \text { cout }<<" 1=\text { yes, } 0=\text { noln" } \\ \text { cin }>>\text { choice } \end{array} \\] }while (choice = 1) return 0 \\} B) // This program displays the sum of the numbers \(1-100\) # include using namespace std; int main () \\{ int count \(=1,\) total; while (count \(<=100\) ) total \(+=\) count cout \(<<\) "The sum of the numbers \(1-100\) is " cout \(<<\) total \(<<\) endl return 0 \\}

Convert the following while loop to a for loop: int count \(=0\) while (count \( < 50\) ) \\{ cout \( < < \) "count is \(" < < \) count \( < < \) endl count \(++\) \\}

Rewrite the following code, converting the while loop to a do-while loop: char doAgain \(=' y^{\prime}\) \\[ \text { int } \operatorname{sum}=0 \\] cout \( < < \) "This code will increment sum 1 or more times. \(| n "\) while ( (doAgain = = ' y') | | (doAgain = = 'Y') ) \(\\{\quad s u m++;\) cout \( < < \) "Sum has been incremented. Increment it again(y/n)? "; cin \(>>\) doAgain; \\} cout \( < < \) "Sum was incremented " \( < < \) sum \( < < "\) times. \(\backslash n "\)

A(n) __________ is a special value that marks the end of a series of values.

A loop that is inside another is called a(n) __________ loop.

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free