Assume \(c\) is a char variable. What value does \(c\) hold after each of the following statements executes? Statement \(\quad\) Contents of \(c\) \(c=\) toupper \(\left(' a^{\prime}\right)\) \(c=\) toupper \(\left(' B^{\prime}\right)\) \(c=\) tolower \(\left(' D^{\prime}\right)\) \(c=\) toupper \(\left(' e^{\prime}\right)\)

Short Answer

Expert verified
1. c = toupper('a'); 2. c = toupper('B'); 3. c = tolower('D'); 4. c = toupper('e'); Answer: 1. 'A' 2. 'B' 3. 'd' 4. 'E'

Step by step solution

01

Statement 1

First, let's find the value of \(c\) after the given statement executes: $$c = \text{toupper} \left(' a^{\prime}\right)$$ Here, the function toupper() is called with the lowercase character 'a'. The function takes this character and returns its uppercase version 'A'. So, after the statement executes, the value of \(c\) will be 'A'.
02

Statement 2

Now, let's find the value of \(c\) after the given statement executes: $$c = \text{toupper} \left(' B^{\prime}\right)$$ The input to the function toupper() is the uppercase character 'B'. Since it's already in uppercase, the function returns 'B' unchanged. So, after the statement executes, the value of \(c\) will be 'B'.
03

Statement 3

Let's find the value of \(c\) after the given statement executes: $$c = \text{tolower} \left(' D^{\prime}\right)$$ Here, the function tolower() is called with the uppercase character 'D'. The function takes this character and returns its lowercase version 'd'. So, after the statement executes, the value of \(c\) will be 'd'.
04

Statement 4

Finally, let's find the value of \(c\) after the given statement executes: $$c = \text{toupper} \left(' e^{\prime}\right)$$ The input to the function toupper() is the lowercase character 'e'. The function takes this character and returns its uppercase version 'E'. So, after the statement executes, the value of \(c\) will be 'E'.

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