Write a function that accepts a pointer to a C-string as its argument. The function should count the number of times the character 'w' occurs in the argument and return that number.

**Question:** Write a function in C that takes a pointer to a C-string as an input and counts the number of occurrences of the character 'w' in it. Provide a step-by-step solution to achieve this. **Answer:** 1. Understand the function signature: The function takes a constant character pointer `str` as its input and returns an integer value representing the number of times 'w' occurs in the string. 2. Write the function header as follows: ```c int countW(const char *str); ``` 3. Initialize a counter variable to store the number of occurrences of 'w', starting at 0: ```c int count = 0; ``` 4. Use a loop to iterate through the C-string character by character until the null terminator '\0' is reached: ```c while (*str != '\0') { // Process the current character str++; } ``` 5. Inside the loop, check if the current character is 'w'. If it is, increment the counter variable: ```c if (*str == 'w') { count++; } ``` 6. After the loop, return the counter variable as the final result: ```c return count; ``` The complete function looks like this: ```c int countW(const char *str) { int count = 0; while (*str != '\0') { if (*str == 'w') { count++; } str++; } return count; } ```