Chapter 10: Problem 37

\(\mathrm{T}\) F If the starting address of a string is passed into a pointer parameter, it can be assumed that all the characters, from that address up to the byte that holds the null terminator, are part of the string.

Short Answer

Expert verified

Answer: True

Step by step solution

Analyze the statement's components

In the given statement, there's a reference to passing the starting address of a string into a pointer parameter. This is common in C programming, where a pointer points to the first character of a string and can be passed as a parameter to a function to access and manipulate the string.

Reason about the null terminator

When working with strings in C, they are terminated by a null character (represented as '\0'). This character indicates the end of the string so that the program knows when to stop reading characters in the string.

Determine if assuming characters are part of the string is accurate

The given statement argues that as long as the starting address of a string is passed into a pointer parameter, we can assume that all characters from that address until the null terminator is encountered are part of the string. This is true as long as the string is well-formed and properly terminated with a null character.

Final answer

Based on the analysis, the given statement is \(\mathrm{T}\) (True). If the starting address of a string is passed into a pointer parameter, it can be assumed that all the characters, from that address up to the byte that holds the null terminator, are part of the string.

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\(\mathrm{T}\) F If the starting address of a string is passed into a pointer parameter, it can be assumed that all the characters, from that address up to the byte that holds the null terminator, are part of the string.

Short Answer

Step by step solution

Analyze the statement's components

Reason about the null terminator

Determine if assuming characters are part of the string is accurate

Final answer

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