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Chapter 14: Problem 38

Object aggregation is useful for creating a(n) _____________ relationship between two classes.

Short Answer

Expert verified
Based on the provided solution, the type of relationship that object aggregation represents between two classes is a "Composite" relationship. This relationship is defined by the "has-a" association that one class has with another class or classes, through the use of object aggregation.

Step by step solution

01

Define Object Aggregation

Object aggregation is a concept in object-oriented programming where a class contains a reference to another class as one of its attributes. It implies a "has-a" relationship between the classes, meaning that one class is composed of another class or classes.
02

Identify the Relationship Type

Since object aggregation highlights the "has-a" relationship formed by containing references to other classes, it helps to create a Composite relationship between two classes.
03

Example

Consider a school system with two classes, 'School' and 'Student'. The 'School' class can have an attribute that stores a list of 'Student' objects, referring to all the students enrolled in the school. In this case, we use object aggregation to create a composite relationship between the 'School' and 'Student' classes.

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Most popular questions from this chapter

Each of the following class declarations has errors. Locate as many as you can. class Box { private: double width; double length; double height; public: Box(double w, l, h) { width = w; length = l; height = h; } Box(Box b) // Copy constructor { width = b.width; length = b.length; height = b.height; } ... Other member functions follow ... };

True or False In order for a function or class to become a friend of another class, it must be declared as such by the class granting it access.

True or False You cannot use the \(=\) operator to assign one object's values to another object, unless you overload the operator.

True or False Static member variables are defined outside their class declaration.

Assume a class named Length exists. Write the header for a member function that overloads cout's \(<<\) operator for that class.
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