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Chapter 15: Problem 34

Write the first line of the declaration for a poodle class. The class should be derived from the Dog class with public base class access.

Short Answer

Expert verified
Question: Write the first line of the declaration for a Poodle class derived from the Dog class with public base class access in C++. Answer: class Poodle : public Dog {

Step by step solution

01

Define the base class

Before creating the derived class, recall that there is a base class called Dog. Here's an example of how the Dog class can be defined: ```cpp class Dog { // Class members and methods for the Dog class }; ```
02

Define the derived class with public inheritance

To create a derived class with public inheritance, use the syntax `class DerivedClass : public BaseClass`. In this case, the DerivedClass is Poodle, and the BaseClass is Dog. The first line of the declaration for the Poodle class will look like this: ```cpp class Poodle : public Dog { // Class members and methods for the Poodle class }; ``` This line of code creates the Poodle class, which is derived from the Dog class with public base class access.

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Most popular questions from this chapter

Each of the class declarations and/or member function definitions below has errors. Find as many as you can. class Table : public Furniture { protected: int numSeats; public: Table(int n) : Furniture(numSeats) { numSeats = n; } ~Table(); };

______ is where a derived class has two or more base classes.

True or False Private members of a protected base class become inaccessible to the derived class.

A(n) ________ class cannot be instantiated.

Complete the table below by filling in private, protected, public, or inaccessible in the right-hand column: $$\begin{array}{ll} \hline \text { In a public base class, this base class } & \ldots \text { becomes this access specification in } \\ \text { MEMBER access specification... } & \text { the derived class. } \\ \hline \text { private } & & \\ \text { protected } & & \\ \text { public } & & \\ \hline \end{array}$$
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