Chapter 15: Problem 36

Suppose a class named Tiger is derived from both the Felis class and the Carnivore class. Here is the first line of the Tiger class declaration: class Tiger : public Felis, public carnivore Here is the function header for the Tiger constructor: Tiger (int \(x,\) int \(y\) ) : Carnivore (x), Felis(y) Which base class constructor is called first, carnivore or Felis?

Short Answer

Expert verified

Answer: The order of constructor calls is Felis constructor followed by Carnivore constructor.

Step by step solution

Understand the class declaration

In the given exercise, the class Tiger is derived from two classes Felis and Carnivore using multiple inheritance. The syntax shows that the Tiger class is publicly inheriting both the base classes.

Analyze the constructor header

The given constructor header for the Tiger class is: Tiger (int \(x,\) int \(y\) ) : Carnivore (x), Felis(y) This header indicates that the Tiger constructor is taking x and y as arguments and passing them to the constructors of the base classes Carnivore and Felis, respectively.

Determine the order of base class constructor calls

In C++, the order of constructor calls for base classes in multiple inheritance depends on the order in which the base classes are listed in the class declaration, not on the order of their appearance in the constructor header. For the given class declaration, the order of base classes is: class Tiger : public Felis, public Carnivore Thus, the Felis constructor is called first, followed by the Carnivore constructor.

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Short Answer

Step by step solution

Understand the class declaration

Analyze the constructor header

Determine the order of base class constructor calls

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