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Chapter 3: Problem 38

include using namespace std; int main() { long x, y, z; x = y = z = 4; x += 2; y -= 1; z *= 3; cout << x << " " << y << " " << z << endl; return 0; } # . #include using namespace std; int main() { long x, y, z; x = y = z = 4; x += 2; y -= 1; z *= 3; cout << x << " " << y << " " << z << endl; return 0; }

Short Answer

Expert verified
Answer: After the program updates the values of the variables according to the specified operations, the final values are as follows: x = 6, y = 3, and z = 12. The output printed to the console is "6 3 12".

Step by step solution

01

Directives and Namespaces

In the beginning, the program uses a directive '#include ', which allows the program to use input and output streams, such as 'cin' and 'cout'. `using namespace std;` line tells the compiler to use the standard C++ library.
02

Main Function

The main function in a C++ program is the entry point for code execution. Here, we have an integer main function that will return 0 upon successful execution.
03

Declare and Initialize Variables

In this step, three long integer variables x, y, and z are declared and assigned an initial value of 4. In C++ code this is done by: long x, y, z; x = y = z = 4;
04

Updating the Values of 'x', 'y', and 'z'

Next, the values of the variables x, y, and z are updated: - x is incremented by 2: x += 2; - y is decremented by 1: y -= 1; - z is multiplied by 3: z *= 3; After these operations, the updated values of x, y, and z are: - x = 4 + 2 = 6; - y = 4 - 1 = 3; - z = 4 * 3 = 12;
05

Print the Results

Using 'cout << x << " " << y << " " << z << endl;', the updated values of 'x', 'y', and 'z' are printed to the console. The output will be: 6 3 12
06

Returning 0

The 'return 0;' statement signifies that the program executed successfully and indicates the end of the 'main' function.

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Most popular questions from this chapter

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