Look at the following array definition. double sales [8][10]; How many rows does the array have? How many columns does the array have? How many elements does the array have? Write a statement that stores a number in the last column of the last row in the array.

Short Answer

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Answer: The array has 8 rows and 10 columns, giving a total of 80 elements. To store a number in the last column of the last row, we can write a statement like this: `sales[7][9] = some_number;`, where `some_number` is the value we want to store in that position.

Step by step solution

01

Determine rows

The array is defined as `double sales[8][10]`. The first dimension (8) represents the number of rows, so the array has 8 rows.
02

Determine columns

The second dimension (10) represents the number of columns. Therefore, the array has 10 columns.
03

Determine number of elements

The total number of elements in the array can be calculated by multiplying the number of rows by the number of columns. In this case, we have 8 rows and 10 columns, so there are 8*10 = 80 elements in the array.
04

Store a number in the last column of the last row

To store a number in the last column of the last row, we need to access the last row (row index 7, since index starts at 0) and the last column (column index 9, since index starts at 0). We can write a statement like this: `sales[7][9] = some_number;` where `some_number` is the value we want to store in that position.

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