Chapter 15: Problem 44

True or False Private members of a protected base class become inaccessible to the derived class.

Short Answer

Expert verified

Answer: True. In both C++ and Java, private members of a base class are always inaccessible to derived classes, regardless of whether the base class is protected or not.

Step by step solution

Understanding Inheritance and Access Specifiers

In both C++ and Java, inheritance is a way to create a new class from an existing one, inheriting the properties and methods of the original class. Access specifiers are used to determine which members/methods of a base class can be accessed or inherited by the derived class.

Private Members: C++ and Java

In both languages, private members of a class are hidden from other classes, including derived classes. Only members and methods within the class containing these private members can access them.

Protected Members: C++ and Java

Protected members are accessible within the class and by derived classes. In C++, protected inheritance means that public and protected members of the base class become protected members of the derived class. In Java, protected members can be accessed by derived classes, as well as classes within the same package.

Conclusion: Statement Verification

The statement in question is as follows: "Private members of a protected base class become inaccessible to the derived class." Considering both C++ and Java, this statement is True. Private members of a base class, regardless of whether the base class is protected or not, are always inaccessible to derived classes.

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True or False Private members of a protected base class become inaccessible to the derived class.

Short Answer

Step by step solution

Understanding Inheritance and Access Specifiers

Private Members: C++ and Java

Protected Members: C++ and Java

Conclusion: Statement Verification

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