Suppose the following operations are performed on an empty stack: push(8); push(7); pop(); push(19); push(21); pop(); Insert numbers in the following diagram to show what will be stored in the static stack after the operations above have executed.

Short Answer

Expert verified
Answer: The remaining elements in the stack are {8, 19}.

Step by step solution

01

Understanding Stack Operation

Stack operates on the principle of "Last in, First out" (LIFO). "push" is an operation which inserts an element into the stack. On the other hand, "pop" is an operation that removes the most recently added element that's not yet been removed. An empty stack is the initial condition in this problem.
02

Perform First Push Operation

The first operation provided in the exercise is push(8). This operation places the number 8 onto the stack.
03

Perform Second Push Operation

The next operation is push(7). This places the number 7 on top of number 8 in the stack.
04

Perform First Pop Operation

The next operation is pop(). This will remove the most recently added number from the stack. In this case, it will remove the number 7.
05

Perform Third Push Operation

Afterwards, push(19) is conducted. This operation adds number 19 on top of the stack which only includes number 8 before.
06

Perform Fourth Push Operation

Afterwards, push(21) is conducted. This operation places number 21 on top of the number 19 in the stack.
07

Perform Second Pop Operation

The final operation is pop(). This operation will remove the most recently added number from the stack which is 21. After all of these operations, the elements left in the stack, from bottom to top, will be {8, 19}.

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