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Chapter 2: Problem 28

Convert the following pseudocode to C++ code. Be sure to define the appropriate variables. Store 172.5 in the force variable. Store 27.5 in the area variable. Divide area by force and store the result in the pressure variable. Display the contents of the pressure variable.

Short Answer

Expert verified
Based on the provided step-by-step solution, answer the following question: Q: Convert the given pseudocode to C++ code. A: ```cpp #include using namespace std; int main() { // Declare variables double force, area, pressure; // Assign values to variables force = 172.5; area = 27.5; // Calculate pressure pressure = area / force; // Display pressure variable cout << "Pressure: " << pressure << endl; return 0; } ```

Step by step solution

01

1. Initialization and Declaration of Variables

First, include the necessary libraries and declare the main function. Then, in the main function, define the variables force, area, and pressure as double to follow the given pseudocode instructions. ```cpp #include using namespace std; int main() { double force, area, pressure; } ```
02

2. Assign Values to Variables

Assign the given values to the force and area variables: ```cpp force = 172.5; area = 27.5; ```
03

3. Calculate Pressure

Divide the area by force and store the result in the pressure variable: ```cpp pressure = area / force; ```
04

4. Display Pressure Variable

Use cout to display the contents of the pressure variable: ```cpp cout << "Pressure: " << pressure << endl; ``` Putting it all together, the final C++ code should look like this: ```cpp #include using namespace std; int main() { // Declare variables double force, area, pressure; // Assign values to variables force = 172.5; area = 27.5; // Calculate pressure pressure = area / force; // Display pressure variable cout << "Pressure: " << pressure << endl; return 0; } ```

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