Write \(\mathrm{C}++\) expressions for the following algebraic expressions: $$\begin{array}{l} a=12 x \\ z=5 x+14 y+6 k \\ y=x^{4} \\ g=\frac{b+12}{4 k} \\ c=\frac{a^{3}}{b^{2} k^{4}} \end{array}$$

Short Answer

Expert verified
Question: Translate the following algebraic expressions into C++ expressions: 1. a = 12x 2. z = 5x + 14y + 6k 3. y = x^4 4. g = (b + 12) / (4k) 5. c = a^3 / (b^2 * k^4) Answer: 1. `a = 12 * x;` 2. `z = 5 * x + 14 * y + 6 * k;` 3. `y = pow(x, 4);` 4. `g = (b + 12) / (4 * k);` 5. `c = pow(a, 3) / (pow(b, 2) * pow(k, 4));`

Step by step solution

01

Expression 1: a = 12x

To translate the algebraic expression "a = 12x", the C++ expression would be: `a = 12 * x;`.
02

Expression 2: z = 5x + 14y + 6k

To translate the algebraic expression "z = 5x + 14y + 6k", the C++ expression would be: `z = 5 * x + 14 * y + 6 * k;`.
03

Expression 3: y = x^4

To translate the algebraic expression "y = x^4", we can use the C++ `pow()` function from the `` library to perform exponentiation: `y = pow(x, 4);`.
04

Expression 4: g = (b + 12) / (4k)

To translate the algebraic expression "g = (b + 12) / (4k)", the C++ expression would be: `g = (b + 12) / (4 * k);`.
05

Expression 5: c = a^3 / (b^2 * k^4)

To translate the algebraic expression "c = a^3 / (b^2 * k^4)", we can use the `pow()` function again for exponentiation, along with the appropriate syntax for multiplication and division operations in C++: `c = pow(a, 3) / (pow(b, 2) * pow(k, 4));`.

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