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Chapter 6: Problem 40

T \(\quad\) F \(\quad\) Function prototypes are terminated with a semicolon.

Short Answer

Expert verified
Answer: True (T)

Step by step solution

01

Understanding Function Prototypes

Function prototypes, also known as function declarations, are used in various programming languages like C and C++. They provide the basic information about the function, such as its name, return type, and expected arguments, allowing the compiler to understand the structure of the function without having the actual function definition at that point in the code. This is useful, especially when working with multiple files and functions that call each other.
02

Correct Way to Write Function Prototypes

A function prototype is usually written before the actual function definition, and is composed of the return type, the function name, and the arguments list, all enclosed in parentheses. It should be noted that the argument types should be specified, but not the variable names. For example, in C and C++ programming languages, a function prototype would look like this: ```cpp return_type function_name(argument_type1, argument_type2, ...); ``` Notice how there is a semicolon at the end of the function prototype.
03

Verifying if Function Prototypes are Terminated with a Semicolon

Based on the correct syntax and examples provided, we can see that function prototypes are indeed terminated with a semicolon in programming languages like C and C++. This helps the compiler recognize the end of a function declaration statement.
04

Conclusion

Given the information above, the statement "Function prototypes are terminated with a semicolon" is True (T).

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Most popular questions from this chapter

\(\mathrm{T} \quad \mathrm{F} \quad\) Many functions may have local variables with the same name.

A program contains the following function. int cube(int num) { return num * num * num; } Write a statement that passes the value 4 to this function and assigns its return value to the variable result.

The _________ statement causes a function to end immediately.

How would a static local variable be useful?

If you are writing a function that accepts an argument and you want to make sure the function cannot change the value of the argument, what do you do?
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