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Chapter 6: Problem 51

\(\mathrm{T} \quad \mathrm{F} \quad\) Initialization of static local variables only happens once, regardless of how many times the function in which they are defined is called.

Short Answer

Expert verified
Answer: True

Step by step solution

01

- Understanding Static Local Variables

Static local variables are a type of variable that retains the value even after the function has completed its execution. By default, a local variable loses its data once the function scope is over. However, a static local variable preserves the data and uses it in the next function call.
02

- Recognizing the Initialization Process of Static Local Variables

When a static local variable is declared, it gets initialized only once during the program's lifespan and not every time when a function is called. This is the unique characteristic of static local variables which sets them apart from the usual local variables.
03

- Illustrating with an Example

Consider a function where a static local variable is defined and initialized. Let's also assume the variable is incremented every time the function is called. Based on the nature of static local variables, the initial value will be retained for the subsequent function calls, and the incremented value will be the one from the last function call and not the initially assigned value.
04

- Conclusion: Review of the Statement

The statement provided in the exercise is indeed True (T). Initialization of static local variables only happens once, regardless of how many times the function in which they are defined is called. This unique property helps in performing tasks where we need to retain the previous value and use it for future operations in other function calls.

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Most popular questions from this chapter

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