Look at the following array definition. int numbers[5] = { 1, 2, 3 }; What value is stored in numbers[2]? What value is stored in numbers[4]?

Short Answer

Expert verified
Answer: The value stored at index 2 is 3, and the value stored at index 4 is 0.

Step by step solution

01

Understanding Array Initialization

In C, when an array is declared with a specific size and initialized with less elements than its size, the remaining elements will be automatically initialized with the value 0. In this case, the array 'numbers' is of size 5, but only three elements are provided (1, 2, and 3). Therefore, the remaining elements (numbers[3] and numbers[4]) will be initialized with the value 0.
02

Find the Value at Index 2

To find the value stored in numbers[2], we can simply look at the array initialization. The array is defined as int numbers[5] = { 1, 2, 3 }; Since array indices start from 0, the element at index 2 is 3. So, the value stored in numbers[2] is 3.
03

Find the Value at Index 4

To find the value stored in numbers[4], recall that the remaining elements of the array (after the initial 1, 2, and 3) will be initialized with the value 0, as explained in Step 1. So, the value stored in numbers[4] is 0.

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