Write the definition of ptr, a pointer to a constant int.

Short Answer

Expert verified
**Answer:** To declare a pointer that points to a constant integer, you use the 'const' keyword along with the data type 'int', followed by an asterisk (*) to indicate it's a pointer. For example, `const int *ptr;`. You can assign the address of a constant integer to the pointer using the address-of operator (&). For instance, if you have a constant integer `const int num = 10;`, you can assign its address to the pointer like this: `ptr = #`.

Step by step solution

01

Declare a constant integer

To start, we need to have a constant integer value for the pointer to point to. Let's create a constant integer with the value 10: ```cpp const int num = 10; ```
02

Declare a pointer to a constant integer

Now let's create a pointer that points to a constant integer. We use the keyword 'const' and the data type 'int' in the definition, along with an asterisk (*) to indicate that it is a pointer: ```cpp const int *ptr; ```
03

Assign the address of the constant integer to the pointer

Finally, we can assign the address of the constant integer 'num' to the pointer 'ptr' using the address-of operator (&): ```cpp ptr = # ```
04

Complete Example

Here is how the complete code would look like: ```cpp #include int main() { const int num = 10; const int *ptr; ptr = # std::cout << "Value of num: " << num << std::endl; std::cout << "Address of num: " << # << std::endl; std::cout << "Value of ptr: " << ptr << std::endl; std::cout << "Value pointed by ptr: " << *ptr << std::endl; return 0; } ```

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free