After the catch block has handled the exception, where does program execution resume?

A try-catch block is used in programming languages, like Java, for handling exceptions. The code that can potentially cause an exception is placed within the try block, while the catch block holds the specific code to handle the exception. When an exception is thrown in the try block, the program execution jumps to the appropriate catch block.

After a catch block has handled the exception, the program execution resumes immediately after the catch block. This means that any code written after the catch block will be executed.

Let's consider a Java example to understand the flow of control better: ``` public class ExceptionExample { public static void main(String[] args) { try { int a = 10; int b = 0; int result = a / b; // This will cause an ArithmeticException System.out.println("This line will not be executed."); } catch (ArithmeticException e) { System.out.println("Exception caught: " + e.getMessage()); // Handling exception } System.out.println("Execution resumed after the catch block."); // This line will be executed after the exception is handled } } ``` In this example, the `try` block contains code that can cause an exception (division by zero). If an exception occurs, the program execution jumps to the corresponding `catch` block. After the exception is handled in the `catch` block, execution resumes with the line `System.out.println("Execution resumed after the catch block.");`, which is written immediately after the catch block.