Chapter 17: Problem 1
Why is it risky to store objects of different types in an ArrayList?
Chapter 17: Problem 1
Why is it risky to store objects of different types in an ArrayList?
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Get started for freeWhen ArrayList is used as a non-generic class, why must you use the cast operator with the get method?
During the process of erasure, when the compiler encounters a generic class,
interface, or method with an unbound type parameter, such as
In generic type notation, what does \(<\) ? super Integer>mean?
Assume that you must define the type parameter \(T\) in a generic method. How would you constrain the type parameter T so it only accepts type arguments that implement the Comparable interface?
During the process of erasure, when the compiler encounters a class,
interface, or method with a bound type parameter, such as
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