Chapter 17: Problem 24
During the process of erasure, when the compiler encounters a class,
interface, or method with a bound type parameter, such as
Chapter 17: Problem 24
During the process of erasure, when the compiler encounters a class,
interface, or method with a bound type parameter, such as
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Get started for freeWhy is it risky to store objects of different types in an ArrayList?
Why would you want to constrain the type parameter in a generic class?
In generic type notation, can you use both extends and super to constrain a type to a set of boundaries?
Assume we have used the statement shown in Checkpoint 17.3 to instantiate the ArrayList class. If we attempt to store an object that is not of the allowable type in the ArrayList, will we see an error message at compile time or at runtime?
In generic type notation, what does \(\) extends Number? mean?
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