Chapter 4: Problem 24

Assume \(x\) is an int variable, and rand references a Random object. What does the following statement do? \(x=\) rand \(.\) next \(\operatorname{Int}(1)\)

Short Answer

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Answer: 0

Step by step solution

Understand the given code

In the given code, 'x' is an integer variable, and 'rand' is a Random object. The statement we need to analyze is: `x = rand.nextInt(1)`

Random object and nextInt method

A Random object, in most programming languages like Java or C#, is an object that generates a random sequence of integers. The nextInt() method is a part of the Random class, which when called with a positive integer n as an argument, generates a random integer 'r' such that \(0 \leq r < n\).

Analyzing the nextInt(1) method call

In the given statement, the nextInt method is called with an argument of 1: `rand.nextInt(1)`. This means that the method should generate a random integer 'r' such that \(0 \leq r < 1\). Since the only integer value that is greater than or equal to 0 and less than 1 is 0, the method will always return 0 as the random integer.

Assigning the random integer to variable 'x'

The code assigns the random integer generated by the nextInt(1) method to the integer variable 'x', so we have: `x = rand.nextInt(1)` which means `x = 0`.

Conclusion

The given statement, `x = rand.nextInt(1)`, always assigns the value 0 to the integer variable 'x' as the nextInt method with an argument of 1 always returns 0.

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Assume \(x\) is an int variable, and rand references a Random object. What does the following statement do? \(x=\) rand \(.\) next \(\operatorname{Int}(1)\)

Short Answer

Step by step solution

Understand the given code

Random object and nextInt method

Analyzing the nextInt(1) method call

Assigning the random integer to variable 'x'

Conclusion

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