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Chapter 4: Problem 7

Write a pseudocode If-Then statement that assigns 0.2 to commission if sales is greater than or equal to 10,000.

Short Answer

Expert verified
Based on the given step-by-step solution, answer the following question: **Question:** Write a pseudocode for an If-Then statement that assigns a value of 0.2 to the commission variable if the sales variable is greater than or equal to 10,000. **Answer:** ```pseudocode DECLARE sales, commission sales = 12000 IF sales >= 10000 THEN commission = 0.2 END IF ```

Step by step solution

01

1. Initialize the variables

First, we need to indicate the variables we will be working with. In this case, we have the 'sales' and 'commission' variables. ``` DECLARE sales, commission ```
02

2. Set values for testing

For testing purposes, we will temporarily set a value for the 'sales' variable. After writing the entire pseudocode, this line can be removed. ``` sales = 12000 ```
03

3. Write the If-Then statement

Next, we write the If-Then statement to compare the value of the 'sales' variable with the given condition (greater than or equal to 10,000). If the condition is true, then assign 0.2 to the 'commission' variable. ``` IF sales >= 10000 THEN commission = 0.2 END IF ```
04

4. Pseudocode overview

Here's the complete pseudocode with all the steps, including the testing value for the 'sales' variable, which can be changed or removed as needed. ``` DECLARE sales, commission sales = 12000 IF sales >= 10000 THEN commission = 0.2 END IF ```

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Most popular questions from this chapter

How does a dual alternative decision structure work?

What is a control structure?

What statement do you use in pseudocode to write a dual alternative decision structure?

The following truth table shows various combinations of the values true and false connected by a logical operator. Complete the table by circling T or \(\mathrm{F}\) to indicate whether the result of such a combination is true or false. $$\begin{array}{lcc} \text { Logical Expression } & \text { Result (circle T or F) } \\ \text { True AND False } & \mathrm{T} & \mathrm{F} \\ \text { True AND True } & \mathrm{T} & \mathrm{F} \\ \text { False AND True } & \mathrm{T} & \mathrm{F} \\ \text { False AND False } & \mathrm{T} & \mathrm{F} \\ \text { True OR False } & \mathrm{T} & \mathrm{F} \\ \text { True or True } & \mathrm{T} & \mathrm{F} \\ \text { False or True } & \mathrm{T} & \mathrm{F} \\ \text { False or False } & \mathrm{T} & \mathrm{F} \\ \text { Not True } & \mathrm{T} & \mathrm{F} \\ \text { NOT False } & \mathrm{T} & \mathrm{F} \end{array}$$

Convert the following pseudocode to an If-Then-Else If statement: If number == 1 Then Display "One" Else If number == 2 Then Display "Two" Else If number == 3 Then Display "Three" Else Display "Unknown" End If End If End If
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