Assume a program has the following declarations: Constant Integer ROWS \(=100\) Constant Integer COLS \(=50\) Declare Integer infol ROWS \(]\) [ \(\cos s\) ] Write pseudocode with a set of nested loops that stores the value 99 in each element of the info array.

Short Answer

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Question: Write a pseudocode for assigning the value 99 to all elements of a 2D array "info" that has 100 rows and 50 columns. Answer: ``` For i = 0 to ROWS - 1 For j = 0 to COLS - 1 info[i][j] = 99 End For End For ```

Step by step solution

01

Initialize outer loop

Start a loop for rows, using an integer variable 'i' that goes from 0 to ROWS-1, as the array index starts at 0: ``` For i = 0 to ROWS - 1 ```
02

Initialize inner loop

Within the outer loop, start an inner loop for columns using an integer variable 'j' that goes from 0 to COLS-1: ``` For j = 0 to COLS - 1 ```
03

Assign the value 99 to each element

Inside the inner loop, assign the value 99 to the element at position (i, j) in the info array: ``` info[i][j] = 99 ```
04

Close the inner loop

As you have assigned the value 99 to the element in the current column, close the inner loop: ``` End For ```
05

Close the outer loop

After assigning the value 99 to all elements in all columns of the current row, close the outer loop: ``` End For ``` Combining all the steps, the final pseudocode is: ``` For i = 0 to ROWS - 1 For j = 0 to COLS - 1 info[i][j] = 99 End For End For ```

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