Chapter 8: Problem 13

Write an if statement that displays "Digit" if the string referenced by the variable ch contains a numeric digit. Otherwise, it should display "No digit."

Short Answer

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Question: Write an if statement that checks if a given variable, ch, contains a numeric digit or not. If it does, the program should display "Digit", otherwise it should display "No digit." Answer: To check if a variable `ch` contains a numeric digit, you can use the Python `isdigit()` method. The if statement would look like this: ``` if ch.isdigit(): print("Digit") else: print("No digit") ```

Step by step solution

Check if ch contains a numeric digit

To check if a variable "ch" contains a numeric digit, we can use the isdigit() method which is a pre-built function in Python. The isdigit() method returns True if the string contains a digit and False otherwise.

Write the if statement

Now that we have a method to check if ch contains a numeric digit, we can use this to create the if statement. If isdigit() returns True, we display "Digit", and if it returns False, we display "No digit." Here is the code based on the previous analysis: """ ch = "5" if ch.isdigit(): print("Digit") else: print("No digit") """

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Write an if statement that displays "Digit" if the string referenced by the variable ch contains a numeric digit. Otherwise, it should display "No digit."

Short Answer

Step by step solution

Check if ch contains a numeric digit

Write the if statement

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