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Chapter 9: Problem 15

Does a set allow you to store duplicate elements?

Short Answer

Expert verified
Answer: No, sets do not allow storing duplicate elements, as they only accept distinct elements.

Step by step solution

01

Define a set

A set is an unordered collection of distinct elements. In mathematics, a set is usually denoted by curly braces enclosing the elements, separated by commas, such as {1, 2, 3}.
02

Explain the distinct element property

A set allows only distinct elements, which means that each element can appear only once in a set. If an element is already in the set, adding it again will not change the set. For example, if we have a set {1, 2, 3}, adding 2 again will result in the same set {1, 2, 3}.
03

Provide examples of sets with and without duplicate elements

Let's consider two examples - a list with duplicate elements and a corresponding set: List: [1, 2, 2, 3, 4, 4, 4, 5] Set: {1, 2, 3, 4, 5} As we can see, the set does not include duplicate elements, even though the original list had them.
04

Conclude the answer

In conclusion, a set does not allow you to store duplicate elements, as it only accepts distinct elements.

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Most popular questions from this chapter

What module do you import if you want to pickle objects?

After the following code executes, what elements will be members of set3? \\[\begin{array}{l}\text { set1 }=\operatorname{set}([1,2,3,4]) \\ \text { set2 }=\operatorname{set}([3,4,5,6]) \\\\\text { set } 3=\text { set } 2 \text { . difference (set1) } \end{array}\\]

After the following code executes, what elements will be members of set3? $$\begin{array}{l}\text { set1 }=\operatorname{set}\left(\left[' a^{\prime}, \quad^{\prime} b^{\prime},\quad^{\prime}c^{\prime}\right]\right) \\ \text { set } 2=\operatorname{set}\left(\left[' b^{\prime}, \quad^{\prime} c^{\prime}, \quad^{\prime} d^{\prime}\right]\right) \\\\\text { set } 3=\text { set1. symmetric }_{-} \text {difference (set2) }\end{array}$$

After the following code executes, what elements will be members of set3? \\[\begin{array}{l}\text { set1 }=\operatorname{set}([1,2,3,4]) \\ \text { set } 2=\operatorname{set}([3,4,5,6]) \\ \text { set } 3=\text { set } 1 . \text { intersection (set2) }\end{array}\\]

What does the items method return?
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