Disney's Hannah Montana: The Movie opened on Easter weekend in April 2009. Over the three-day weekend, the movie became the number-one box office attraction (The Wall Street Journal, April 13,2009 ). The ticket sales revenue in dollars for a sample of 25 theaters is as follows. $$\begin{array}{rrrrr} 20,200 & 10,150 & 13,000 & 11,320 & 9,700 \\ 8,350 & 7,300 & 14,000 & 9,940 & 11,200 \\ 10,750 & 6,240 & 12,700 & 7,430 & 13,500 \\ 13,900 & 4,200 & 6,750 & 6,700 & 9,330 \\ 13,185 & 9,200 & 21,400 & 11,380 & 10,800 \end{array}$$ a. What is the \(95 \%\) confidence interval estimate for the mean ticket sales revenue per theater? Interpret this result. b. Using the movie ticket price of \(\$ 7.16\) per ticket, what is the estimate of the mean number of customers per theater? c. The movie was shown in 3118 theaters. Estimate the total number of customers who saw Hannah Montana: The Movie and the total box office ticket sales for the threeday weekend.

Short Answer

Expert verified
The 95% confidence interval estimate for the mean ticket sales revenue per theater is \(\$10,614.76 \pm \$1,603.61\) which means we're 95% confident that the true mean ticket sales revenue for all theaters lies within this range. The estimated mean number of customers per theater is approximately 1,481. Using these estimations, the total number of customers who saw Hannah Montana: The Movie over the three-day weekend in 3,118 theaters is around 4,617,018, and the total box office ticket sales revenue is approximately \$33,103,919.

Step by step solution

01

Calculate sample mean and standard deviation

First, we need to add up all the revenues and divide by the number of theaters (25) to find the mean. Next, we'll calculate the standard deviation by finding the differences between each revenue and the mean, squaring them, adding them up, dividing by the degrees of freedom (n - 1), and then taking the square root of the result.
02

Calculate the 95% confidence interval estimate

To calculate the confidence interval, we will use a t-distribution since our sample size is small (25 theaters) and we don't know the population standard deviation. The formula for the confidence interval is: \(\bar{x} \pm t_{\alpha/2, df} \cdot \frac{s}{\sqrt{n}}\) where \(\bar{x}\) is the sample mean, \(t_{\alpha/2, df}\) is the t-value for our desired level of confidence (95%) and degrees of freedom (n-1), \(s\) is the sample standard deviation, and \(n\) is the sample size. Once we find the t-value, we'll multiply it by the standard error (\(s/\sqrt{n}\)) and then add and subtract this value from the sample mean.
03

Estimate the mean number of customers per theater

Now that we have the mean ticket sales revenue, we'll use the given ticket price of $7.16 per ticket to estimate the mean number of customers per theater. We can do this simply by dividing the mean ticket sales revenue by the ticket price: Mean number of customers per theater = \(\frac{\bar{x}}{ticket\_price}\)
04

Estimate the total number of customers and ticket sales

Finally, we'll estimate the total number of customers who saw the movie and the total box office ticket sales for the three-day weekend. To do this, we'll multiply our estimates from Steps 3 and 1, respectively, by the total number of theaters (3,118). The results will give us the estimated total number of customers and the total box office ticket sales revenue for the three-day weekend. Total number of customers = Mean number of customers per theater (Step 3) × Total number of theaters Total ticket sales revenue = Mean ticket sales revenue per theater (Step 1) × Total number of theaters

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean, denoted as \( \bar{x} \), is a measure of the central tendency of a set of data. It represents the average value in a sample and is calculated by summing all the numbers in the sample and then dividing by the quantity of numbers.

In the context of the Hannah Montana movie revenue example, the sample mean of ticket sales revenue was computed by adding the revenue from each of the 25 theaters and dividing by 25. This gave us the average ticket sales revenue per theater. Understanding the calculation of the sample mean is crucial, as it is a building block for many statistical measures and is used directly in the computation of the confidence interval in further steps of the exercise.

Knowing how to calculate and interpret the sample mean allows students to ascertain the general performance of a group, such as the average earnings from ticket sales across a selection of theaters in a given time period.
Standard Deviation
Standard deviation is a statistic that measures the amount of variability or dispersion around the mean of a set of values. It indicates how spread out the numbers in your data are, with a high standard deviation signifying that the data points are widely scattered from the mean, and a low standard deviation indicating that they are closely clustered.

To calculate the standard deviation, which is symbolized as \( s \), you subtract the sample mean from each data point, square the result to make it positive, average these squared differences by dividing by the number of data points minus 1 (to account for sample data, known as degrees of freedom), and finally take the square root of this average. In our exercise, the standard deviation of ticket sales revenue helps us understand the consistency of revenue across different theaters.

Note: When dealing with a sample rather than an entire population, we use 's' to represent the standard deviation and we divide by \( n-1 \) (degrees of freedom) rather than \( n \) when calculating the variance (which is the square of the standard deviation).
T-distribution
The t-distribution is a type of probability distribution that is symmetric and bell-shaped, like the normal distribution, but it has heavier tails. This means that it predicts a greater number of extreme values than the normal distribution. It is particularly useful when dealing with small sample sizes or when the population standard deviation is unknown, both of which apply to the Hannah Montana exercise scenario.

When constructing a confidence interval estimate with a t-distribution, we use the t-score, which adjusts for the size of the sample. If you have a larger sample size, the t-distribution approaches the normal distribution. The relevant formula for the confidence interval using the t-distribution is:
\[ \bar{x} \pm t_{\alpha/2, df} \cdot \frac{s}{\sqrt{n}} \]
where \( t_{\alpha/2, df} \) is the t-score that corresponds to the desired confidence level and degrees of freedom (df), which is \( n-1 \). In our movie theater example, the t-distribution is used to estimate the mean ticket sales revenue with a 95% confidence interval, reflecting the uncertainty due to the small sample size.

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Most popular questions from this chapter

The average cost of a gallon of unleaded gasoline in Greater Cincinnati was reported to be \(\$ 2.41(\text {The Cincinnati Enquirer, } \text { February } 3,2006\) ). During periods of rapidly changing prices, the newspaper samples service stations and prepares reports on gasoline prices frequently. Assume the standard deviation is \(\$ .15\) for the price of a gallon of unleaded regular gasoline, and recommend the appropriate sample size for the newspaper to use if it wishes to report a margin of error at \(95 \%\) confidence. a. Suppose the desired margin of error is \(\$ .07\) b. Suppose the desired margin of error is \(\$ .05\) c. Suppose the desired margin of error is \(\$ .03\)

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