During the first quarter of \(2003,\) the price/earnings (P/E) ratio for stocks listed on the New York Stock Exchange generally ranged from 5 to 60 (The Wall Street Journal, March 7 , 2003 ). Assume that we want to estimate the population mean P/E ratio for all stocks listed on the exchange. How many stocks should be included in the sample if we want a margin of error of \(3 ?\) Use \(95 \%\) confidence.

Short Answer

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To estimate the population mean P/E ratio for all stocks listed on the New York Stock Exchange with a margin of error of 3 and a 95% confidence level, a minimum sample size of 81 stocks is needed.

Step by step solution

01

To find the corresponding Z-score for a 95% confidence level, we can use a standard normal distribution table (also known as a Z-table) or a calculator with the inverse cumulative distribution function. The Z-score for a 95% confidence level is approximately 1.96. #Step 2: Substitute values into the formula#

Now, we can substitute the values into the sample size formula: \(n = (\frac{1.96 \cdot 13.75}{3})^2\) #Step 3: Calculate sample size#
02

Calculate the sample size: \(n \approx (\frac{26.98}{3})^2 \approx (8.99)^2 \approx 80.82\) Since we cannot have a part of a stock, we will need to round up to the next whole number. #Step 4: Round up and find the final sample size#

The minimum sample size needed to achieve a margin of error of 3 with a 95% confidence level is 81.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Mean
When discussing statistics and sampling, the 'population mean' is a term that refers to the average value of a particular characteristic across the entire population. For example, in the context of the financial industry, if one wishes to understand the average Price-to-Earnings (P/E) ratio of all stocks listed on the New York Stock Exchange, the population mean would be the value to seek. Estimating the population mean with precision typically involves taking a randomly selected sample from the population and calculating the mean of that sample.

To ensure that this estimation is likely to reflect the population mean, an adequate sample size must be chosen. The population mean is a crucial starting point because any inaccuracy in its estimation will be reflected in subsequent statistical inferences or hypotheses tests about the population.
Confidence Level
A 'confidence level' is a measure of certainty regarding the reliability of an estimate. It indicates the probability that the actual population parameter falls within a range, known as a confidence interval, around the estimated value. For instance, a 95% confidence level means that if 100 random samples were taken, the resulting confidence intervals from those samples would be expected to contain the actual population parameter 95 times out of 100. This confidence level is not about the likelihood of one sample being correct, but rather speaks to the long-term accuracy rate of the estimation process when repeated multiple times.

The choice of confidence level is dependent on how much risk of error one is willing to accept; higher confidence levels will result in a larger confidence interval, meaning a wider range of values around the estimated mean. In practice, common confidence levels include 90%, 95%, and 99% — with 95% being a standard choice in many fields, including the case of the P/E ratio estimation.
Margin of Error
The 'margin of error' represents the extent to which an estimate obtained from a sample can differ from the true population parameter and still be considered accurate. Essentially, it quantifies the maximum expected difference between the sample estimate and the actual population value. The margin of error is influenced by two main factors: the level of confidence desired (with higher confidence necessitating a larger margin) and the variability within the population data. Narrower margins of error require larger sample sizes to maintain the same level of confidence.

In the P/E ratio estimation problem, a margin of error of 3 means we allow the sample mean to be within 3 units of the true population mean. A smaller margin of error, while desirable for more precise estimates, often necessitates a bigger sample which can be more costly or time-consuming to obtain.
Z-score
In statistical analysis, the 'Z-score' is a standardized score that indicates the number of standard deviations a data point is from the population mean. Z-scores are used to calculate the probabilities of a score occurring within a normal distribution and are a key component in finding the correct sample size for estimating a population parameter with a specified confidence level and margin of error.

To determine the required sample size for our P/E ratio estimation with a 95% confidence level, we first identify the Z-score that corresponds to this level of confidence. For 95% confidence level, the Z-score is typically 1.96. This value is used in the sample size formula and reflects the number of standard deviations required to encapsulate 95% of the data in a normal distribution, ensuring that our estimated interval will likely contain the true population mean.
Normal Distribution
The 'normal distribution' is a continuous probability distribution that is symmetrical around the mean, showing that data near the mean are more frequent in occurrence than data far from the mean. Also known as the Gaussian distribution, it is the foundational probability curve in statistics because of its widespread occurrences in natural and social phenomena.

When estimating the sample size for the P/E ratio problem, we assume that the distribution of P/E ratios is normally distributed, even though we don't know the actual distribution. This assumption allows us to use the standard normal distribution and its properties to determine the Z-score and subsequently the sample size. For a 95% confidence level, the Z-score tells us how many standard deviations away from the mean capture the central 95% of the data in a normal distribution, informing our calculations for estimate precision.

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Most popular questions from this chapter

America's young people are heavy Internet users; \(87 \%\) of Americans ages 12 to 17 are Internet users (The Cincinnati Enquirer, February 7,2006 ). MySpace was voted the most popular website by \(9 \%\) in a sample survey of Internet users in this age group. Suppose 1400 youths participated in the survey. What is the margin of error, and what is the interval estimate of the population proportion for which MySpace is the most popular website? Use a \(95 \%\) confidence level.

A \(U S A\) Today/CNN/Gallup survey of 369 working parents found 200 who said they spend too little time with their children because of work commitments. a. What is the point estimate of the proportion of the population of working parents who feel they spend too little time with their children because of work commitments? b. At \(95 \%\) confidence, what is the margin of error? c. What is the \(95 \%\) confidence interval estimate of the population proportion of working parents who feel they spend too little time with their children because of work commitments?

A survey conducted by the American Automobile Association showed that a family of four spends an average of \(\$ 215.60\) per day while on vacation. Suppose a sample of 64 families of four vacationing at Niagara Falls resulted in a sample mean of \(\$ 252.45\) per day and a sample standard deviation of \(\$ 74.50\) a. Develop a \(95 \%\) confidence interval estimate of the mean amount spent per day by a family of four visiting Niagara Falls. b. Based on the confidence interval from part (a), does it appear that the population mean amount spent per day by families visiting Niagara Falls differs from the mean reported by the American Automobile Association? Explain.

The mean number of hours of flying time for pilots at Continental Airlines is 49 hours per month (The Wall Street Journal, February 25, 2003). Assume that this mean was based on actual flying times for a sample of 100 Continental pilots and that the sample standard deviation was 8.5 hours. a. \(\quad\) At \(95 \%\) confidence, what is the margin of error? b. What is the \(95 \%\) confidence interval estimate of the population mean flying time for the pilots? c. The mean number of hours of flying time for pilots at United Airlines is 36 hours per month. Use your results from part (b) to discuss differences between the flying times for the pilots at the two airlines. The Wall Street Journal reported United Airlines as having the highest labor cost among all airlines. Does the information in this exercise provide insight as to why United Airlines might expect higher labor costs?

Mileage tests are conducted for a particular model of automobile. If a \(98 \%\) confidence interval with a margin of error of 1 mile per gallon is desired, how many automobiles should be used in the test? Assume that preliminary mileage tests indicate the standard deviation is 2.6 miles per gallon.

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