A \(95 \%\) confidence interval for a population mean was reported to be 152 to \(160 .\) If \(\sigma=15\) what sample size was used in this study?

Short Answer

Expert verified
The sample size used in this study was approximately 58.

Step by step solution

01

Determine the sample mean and Z-score

Since we know the confidence interval is 152 to 160, we can determine the sample mean (\(\bar{X}\)) by finding the midpoint of this interval: \(\bar{X} = \frac{152 + 160}{2} = 156\) The Z-score for a 95% confidence interval can be found using a standard normal distribution table, which is approximately 1.96.
02

Rearrange the confidence interval formula to solve for n

We have the formula for the confidence interval: CI = \(\bar{X} \pm Z \frac{\sigma}{\sqrt{n}}\) First, subtract the sample mean from both sides of the equation to isolate the margin of error: Margin of Error = \(Z \frac{\sigma}{\sqrt{n}}\) Now, divide both sides by the Z-score: \(\frac{Margin of Error}{Z} = \frac{\sigma}{\sqrt{n}}\) To solve for n, square both sides of the equation: \(\left(\frac{Margin of Error}{Z}\right)^2 = \frac{\sigma^2}{n}\) Then, take the reciprocal of both sides to get n: \(n = \frac{\sigma^2}{\left(\frac{Margin of Error}{Z}\right)^2}\)
03

Plug in the known values into the formula

Now we can plug in the given values: - Margin of Error = \(\frac{160-152}{2} = 4\) - σ = 15 - Z = 1.96 \(n = \frac{15^2}{\left(\frac{4}{1.96}\right)^2}\)
04

Calculate the sample size

By solving the equation, we can find the sample size: \(n = \frac{225}{\left(\frac{4}{1.96}\right)^2} \approx 57.9827\) Since the sample size has to be a whole number, we round up to the nearest integer: n = 58 Thus, a sample size of 58 was used in this study.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Mean
The population mean, often represented by the Greek letter \( \mu \), is a measure that reflects the average of a particular characteristic of an entire group or population. Picture a large group of individuals or items, and the population mean is the average value of a specific trait they all share, such as height, weight, or test score. When it's not feasible to measure every single entity in the population, a sample mean (\(\bar{X}\)) can be used as an estimated value. This is calculated by adding together all of the measured values from a sample (a smaller, selected group from the population) and dividing by the number of observations in the sample. In our exercise, the sample mean was used as a foundational figure in determining the confidence interval for the population mean.

Sample Size Determination
Determining the correct sample size is crucial for any study, as it impacts the accuracy and reliability of the results. It's a balance between practical constraints, like cost and time, and the desired precision of the estimates. The larger the sample size, the closer we get to the actual population mean, but increasing sample size may involve higher costs and more time consuming data collection. The central question of sample size determination is figuring out how large a sample should be to accurately estimate the population parameters with a given level of confidence. It involves complex calculations that take into account the variability of the data (\( \sigma \), the standard deviation), the desired level of precision (margin of error), and the desired confidence level (which affects the Z-score).

Our exercise illustrates how we can work backwards: using the confidence interval and standard deviation to deduce the sample size employed in the study.
Z-score
A Z-score is a statistical measurement that describes a value's relationship to the mean of a group of values, measured in terms of standard deviations from the mean. If a Z-score is 0, it indicates that the data point's score is identical to the mean score. In the context of confidence intervals, Z-scores are used to determine how far the margin of error extends from the mean. These scores come from the standard normal distribution. For a 95% confidence interval, the Z-score is typically 1.96, which signifies that the confidence interval extends 1.96 standard deviations on either side of the mean. The exercise used this Z-score to help calculate the sample size.

Standard Normal Distribution
The standard normal distribution, also known as the Z-distribution, is a special case of the normal distribution that is centered at zero and has a standard deviation of one. It is used in various statistical analyses because of its property where areas under the curve correspond to percentiles. This means that we can calculate the probability of a random variable falling within a certain range. The Z-score is essentially the number of standard deviations away from the mean a data point is, and it corresponds to a certain area under the standard normal distribution curve. This concept is integral when calculating confidence intervals, as it allows us to specify the range within which we can expect the true population parameter to lie with a certain level of confidence.

Margin of Error
The margin of error represents the extent of the range around the sample mean within which we can be relatively certain the true population mean lies. It's part of creating a confidence interval, which is an estimated range of values that is likely to include the population parameter. The margin of error is affected by the sample size and the variability in the data, as well as the confidence level one wishes to have in the interval estimate. In simpler terms, it tells us how 'wrong' our estimate could be. In the exercise, we calculated the margin of error using the given confidence interval and used it alongside the known standard deviation and Z-score to determine the required sample size.

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