AARP reported on a study conducted to learn how long it takes individuals to prepare their federal income tax return \((A A R P \text { Bulletin, April } 2008\) ). The data contained in the file named TaxReturn are consistent with the study results. These data provide the time in hours required for 40 individuals to complete their federal income tax returns. Using past years' data, the population standard deviation can be assumed known with \(\sigma=9\) hours. What is the \(95 \%\) confidence interval estimate of the mean time it takes an individual to complete a federal income tax return?

Short Answer

Expert verified
The 95% confidence interval estimate of the mean time it takes an individual to complete a federal income tax return is (\(x̄ - 2.793\), \(x̄ + 2.793\)) hours, where x̄ is the sample mean of time taken by 40 individuals.

Step by step solution

01

Calculate the sample mean

To calculate the sample mean (x̄), we need to sum up the time it took each individual to complete their federal income tax return and divide it by the sample size (n = 40). The data is not given in the exercise, but we assume that the sample mean has been calculated by summing up the hours and dividing by 40. Let's denote the sample mean as x̄.
02

Find the z-score for the 95% confidence interval

Since we are calculating a 95% confidence interval, that means we have 2.5% in the left tail and 2.5% in the right tail. To find the z-score that corresponds to the 95% confidence interval, we can look it up in a z-table or use software to find the appropriate z-score. The z-score for a 95% confidence interval is approximately 1.96.
03

Calculate the standard error of the sample mean

To calculate the standard error of the sample mean, we will use the formula: \(SE = \frac{\sigma}{\sqrt{n}}\) Where SE is the standard error, σ is the population standard deviation (9 hours), and n is the sample size (40). Plugging in the values, we get: \(SE = \frac{9}{\sqrt{40}} \approx 1.425\)
04

Calculate the margin of error

To calculate the margin of error, we will use the formula: \(ME = Z \times SE\) Where ME is the margin of error, Z is the z-score (1.96) and SE is the standard error (1.425). Plugging in the values, we get: \(ME = 1.96 \times 1.425 \approx 2.793\)
05

Calculate the 95% confidence interval

To calculate the 95% confidence interval, we will use the formula: \(CI = (\bar{x} - ME, \bar{x} + ME)\) Where x̄ is the sample mean and ME is the margin of error (2.793). Plugging in the values, we get: \(CI = (\bar{x} - 2.793, \bar{x} + 2.793)\) So, the 95% confidence interval estimate of the mean time it takes an individual to complete a federal income tax return is (\(x̄ - 2.793\), \(x̄ + 2.793\)) hours.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Population Standard Deviation
When you encounter the term population standard deviation, it refers to the measure of variation or spread in a set of values. In simpler terms, it quantifies how much the numbers in a complete population differ from the population's average value, known as the mean.

In our exercise, the population standard deviation is denoted by the Greek letter sigma \( \sigma \) and is given as 9 hours. This means, on average, the individual completion times vary by 9 hours from the mean completion time for the entire population. Knowing this value is crucial because it's used to calculate the standard error when constructing confidence intervals—if the standard deviation is large, the spread of individual times is more considerable, which would typically lead to a broader confidence interval.
Sample Mean Calculation Basics
The sample mean calculation is a fundamental step in statistical analysis. It represents the average of a sample and is computed by summing all the measurements in the sample and then dividing by the number of observations.

In the provided exercise, the sample mean, represented as \( \bar{x} \), is the average time it takes for the 40 individuals to complete their tax returns. Although the exact data points aren't listed, we're informed that the sample mean \( \bar{x} \) was obtained by summing the tax return completion times for all individuals involved and then dividing by the total number of individuals, which is 40 in this case. This value is a critical component in finding our confidence interval estimate.
Deciphering the Z-score
A Z-score is a statistical metric that describes a value's relationship to the mean of a group of values, measured in terms of standard deviations. It is used in the construction of confidence intervals to determine how far, and in what direction, the data deviates from the mean.

For a 95% confidence interval, the Z-score corresponds to the point on the normal distribution that captures 95% of all possible sample means. In the exercise, the Z-score of approximately 1.96 tells us that 95% of all possible sample means fall within 1.96 standard deviations of the population mean. This specific Z-score is a critical value for calculating the margin of error.
Standard Error Explained
The standard error (SE) quantifies the variability of the sample mean estimate of a population parameter. It essentially tells us how far the sample mean is likely to be from the true population mean.

To calculate it, we divide the population standard deviation by the square root of the number of observations in the sample \( \sqrt{n} \). In the given exercise, the standard error helps in assessing the extent to which the sample mean (\( \bar{x} \) ) may differ from the actual population mean. It is a factor in determining the width of the confidence interval: the larger the standard error, the less certain we are about the sample mean representing the true population mean, thus leading to a wider interval.
Margin of Error Breakdown
Lastly, the margin of error (ME) reflects the range above and below the sample mean within which we can expect the actual population mean to lie. It accounts for possible sampling variability and is influenced by the standard error and the confidence level of the interval.

In the step-by-step solution, we multiply the Z-score by the standard error to find the margin of error. This margin determines how much room there is for potential discrepancies between the sample mean and the true population mean. The calculated margin of error then helps us create the confidence interval by adding and subtracting it from the sample mean, giving us a range that should contain the true mean with 95% certainty.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The travel-to-work time for residents of the 15 largest cities in the United States is reported in the 2003 Information Please Almanac. Suppose that a preliminary simple random sample of residents of San Francisco is used to develop a planning value of 6.25 minutes for the population standard deviation. a. If we want to estimate the population mean travel-to-work time for San Francisco residents with a margin of error of 2 minutes, what sample size should be used? Assume \(95 \%\) confidence b. If we want to estimate the population mean travel-to-work time for San Francisco residents with a margin of error of 1 minute, what sample size should be used? Assume \(95 \%\) confidence

A \(U S A\) Today/CNN/Gallup survey of 369 working parents found 200 who said they spend too little time with their children because of work commitments. a. What is the point estimate of the proportion of the population of working parents who feel they spend too little time with their children because of work commitments? b. At \(95 \%\) confidence, what is the margin of error? c. What is the \(95 \%\) confidence interval estimate of the population proportion of working parents who feel they spend too little time with their children because of work commitments?

The following sample data are from a normal population: 10,8,12,15,13,11,6,5 a. What is the point estimate of the population mean? b. What is the point estimate of the population standard deviation? c. With \(95 \%\) confidence, what is the margin of error for the estimation of the population mean? d. What is the \(95 \%\) confidence interval for the population mean?

A survey conducted by the American Automobile Association showed that a family of four spends an average of \(\$ 215.60\) per day while on vacation. Suppose a sample of 64 families of four vacationing at Niagara Falls resulted in a sample mean of \(\$ 252.45\) per day and a sample standard deviation of \(\$ 74.50\) a. Develop a \(95 \%\) confidence interval estimate of the mean amount spent per day by a family of four visiting Niagara Falls. b. Based on the confidence interval from part (a), does it appear that the population mean amount spent per day by families visiting Niagara Falls differs from the mean reported by the American Automobile Association? Explain.

Consumption of alcoholic beverages by young women of drinking age has been increasing in the United Kingdom, the United States, and Europe (The Wall Street Journal, February 15,2006 ). Data (annual consumption in liters) consistent with the findings reported in The Wall Street Journal article are shown for a sample of 20 European young women. $$\begin{array}{crrrr} 266 & 82 & 199 & 174 & 97 \\ 170 & 222 & 115 & 130 & 169 \\ 164 & 102 & 113 & 171 & 0 \\ 93 & 0 & 93 & 110 & 1300 \end{array}$$ a. What is the \(95 \%\) confidence interval estimate for the mean ticket sales revenue per theater? Interpret this result. b. Using the movie ticket price of \(\$ 7.16\) per ticket, what is the estimate of the mean number of customers per theater? c. The movie was shown in 3118 theaters. Estimate the total number of customers who saw Hannah Montana: The Movie and the total box office ticket sales for the three- day weekend.

See all solutions

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free