John's Lawn Moving Service is a small business that acts as a price taker (i.e., \(M R=P\) ). The prevailing market price of lawn mowing is \(\$ 20\) per acre. John's costs are given by \\[ \text { total cost }=. l q^{2}+l O q+50 \\] where \(q=\) the number of acres John chooses to cut a day. a. How many acres should John choose to cut in order to maximize profit? b. Calculate John's maximum daily profit. c. Graph these results and label John's supply curve.

Short Answer

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#Short Answer# To maximize his profit, John should mow the optimal quantity of acres, which can be calculated by setting the marginal cost (MC) equal to the marginal revenue (MR). In this situation, it is given that MR is \$20. First, find the MC by taking the derivative of the total cost (TC) function with respect to the quantity (q). By setting MC equal to MR and solving for q, we can determine the optimal quantity for John to mow. Then, calculate John's total revenue (TR) and the profit at the optimal quantity. Finally, graph the marginal cost, marginal revenue, and supply curve to visualize the results. The supply curve represents the relationship between the price and quantity supplied, and the intersection of MC and MR curves indicates the optimal quantity for John to maximize his profit.

Step by step solution

01

Find the marginal cost

To find the marginal cost (MC), we need to first take the derivative of the total cost (TC) function with respect to the quantity (q). The given total cost function is: \\[TC = .lq^2 + l O q + 50\\] Taking the derivative with respect to q, we get: \\[MC = \frac{d(TC)}{dq} = .2lq + l O\\]
02

Set marginal cost equal to marginal revenue

Since John's Lawn Mowing Service is a price taker and the given market price is \$20, the marginal revenue (MR) is equal to the price, which is \$20. Now, set the marginal cost equal to the marginal revenue: \\[MC = MR\\] \\[.2lq + l O = 20\\]
03

Solve for the optimal quantity

In order to find the optimal quantity (q), we need to solve the equation we derived in the previous step for q: \\[q = \frac{20-lO}{.2l}\\]
04

Plug the optimal quantity back into the total cost function

Plug the optimal quantity (q) from Step 3 back into the total cost function (TC) to find the total cost at the optimal quantity: \\[TC = .l \left(\frac{20-l O}{.2l}\right)^2 + l O \left(\frac{20-l O}{.2l}\right) + 50\\]
05

Calculate the total revenue at the optimal quantity

The total revenue (TR) at the optimal quantity is the product of the price per acre (P) and the optimal quantity (q): \\[TR = P \times q = 20 \times \frac{20-l O}{.2l}\\]
06

Calculate the profit at the optimal quantity

Now, we can calculate the profit at the optimal quantity, which is the difference between the total revenue (TR) and the total cost (TC) at the optimal quantity: \\[\text{Profit} = TR - TC\\]
07

Graph the marginal cost, marginal revenue and supply curve

Based on the results from Steps 1-6, we can now create a graph with three curves: marginal cost (MC), marginal revenue (MR), and the supply curve. The supply curve can be found by setting the marginal cost (MC) equal to the various prices (P) and solving for q. The intersection of the MC and MR curves represents the optimal quantity, and the supply curve shows the relationship between price and quantity supplied. To conclude, by following the steps provided, a student can find the optimal quantity of acres for John to cut in order to maximize profit, calculate John's maximum daily profit, and graph the outcomes along with the supply curve.

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