$$x^{2}+8 x=-7$$ $$\begin{array}{cc}\text { Quantity } \mathbf{A} & \text { Quantity } \mathbf{B} \\ x & 0 \end{array}$$ a. Quantity A is greater. b. Quantity B is greater. c. The two quantities are equal d. The relationship cannot be determined from the information given.

Short Answer

Expert verified
Quantity B is greater.

Step by step solution

01

Rearrange the Equation

First rearrange the equation to standard quadratic form \(ax^2 + bx + c = 0\). So for our equation, we'll write it as \(x^{2}+8 x + 7 = 0\)
02

Factoring the Quadratic Equation

Here, we need to factor this quadratic equation. We are basically looking for two numbers that add up to 8 and multiply to 7. These numbers are 7 and 1. So, our factored equation becomes \((x+7)(x+1) = 0\)
03

Solving for x

Set each factor to zero and solve for x. Doing so gives the solutions \(x+7=0\) implies \(x=-7\) and \(x+1=0\) implies \(x=-1\)
04

Comparing Quantities

Now, we can compare these two solutions of \(x\) which are Quantity A with 0 which is Quantity B. As we can see, both solutions \(x = -7\) and \(x = -1\) are less than 0. So Quantity B is greater.

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